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\begin{center}
Beispiel zur $(k,s)$-Lupanov-Darstellung Boolescher Funktionen
\end{center}
\begin{itemize}
\item
eine Funktion $f\,:\,\mathcal{B}^6 \rightarrow \mathcal{B}$ 
mit $k=3, s=3, s' = 2$ :

\begin{tabular}{c c c || c c c c c c c c | c }
      &       & $x_4$ & 0 & 1 & 0 & 1 & 0 & 1 & 0 & 1 & \\
      &       & $x_5$ & 0 & 0 & 1 & 1 & 0 & 0 & 1 & 1 & \\
      &       & $x_6$ & 0 & 0 & 0 & 0 & 1 & 1 & 1 & 1 & \\
$x_1$ & $x_2$ & $x_3$ &   &   &   &   &   &   &   &   & \\ \hline\hline
  0   &   0   &   0   & 0 & 1 & 0 & 0 & 0 & 1 & 0 & 0 & \\
  0   &   0   &   1   & 0 & 1 & 1 & 0 & 0 & 1 & 1 & 1 & $A_1$ \\
  0   &   1   &   0   & 1 & 0 & 0 & 1 & 0 & 0 & 0 & 1 & \\ \hline
  0   &   1   &   1   & 1 & 0 & 1 & 1 & 0 & 0 & 1 & 0 & \\
  1   &   0   &   0   & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 1 & $A_2$ \\
  1   &   0   &   1   & 1 & 1 & 0 & 1 & 1 & 0 & 0 & 0 & \\ \hline
  1   &   1   &   0   & 1 & 0 & 1 & 1 & 0 & 1 & 1 & 0 & \\
  1   &   1   &   1   & 0 & 1 & 0 & 0 & 0 & 0 & 1 & 0 & $A_3$ \\
\end{tabular}

\item
die Funktion $f_2 \,:\,\mathcal{B}^6 \rightarrow \mathcal{B}$

\begin{tabular}{c c c || c c c c c c c c | c }
      &       & $x_4$ & 0 & 1 & 0 & 1 & 0 & 1 & 0 & 1 & \\
      &       & $x_5$ & 0 & 0 & 1 & 1 & 0 & 0 & 1 & 1 & \\
      &       & $x_6$ & 0 & 0 & 0 & 0 & 1 & 1 & 1 & 1 & \\
$x_1$ & $x_2$ & $x_3$ &   &   &   &   &   &   &   &   & \\ \hline\hline
  0   &   0   &   0   & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & \\
  0   &   0   &   1   & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & $A_1$ \\
  0   &   1   &   0   & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & \\ \hline
  0   &   1   &   1   & 1 & 0 & 1 & 1 & 0 & 0 & 1 & 0 & \\
  1   &   0   &   0   & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 1 & $A_2$ \\
  1   &   0   &   1   & 1 & 1 & 0 & 1 & 1 & 0 & 0 & 0 & \\ \hline
  1   &   1   &   0   & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & \\
  1   &   1   &   1   & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & $A_3$ \\
\end{tabular}

\item
die Funktion $f_{2,\mathbf{v}}^{(r)}$ f\"ur $\mathbf{v} = (1\,0\,1)^t$
und f\"ur $\mathbf{v} = (0\,1\,1)^t$

\begin{tabular}{c c c || c | c }
$x_1$ & $x_2$ & $x_3$ &   & \\ \hline\hline
  0   &   0   &   0   & 0 & \\
  0   &   0   &   1   & 0 & $A_1$ \\
  0   &   1   &   0   & 0 & \\ \hline
  0   &   1   &   1   & 1 & \\
  1   &   0   &   0   & 0 & $A_2$ \\
  1   &   0   &   1   & 1 & \\ \hline
  1   &   1   &   0   & 0 & \\
  1   &   1   &   1   & 0 & $A_3$ \\
\end{tabular}
\hskip25mm
\begin{tabular}{c c c || c | c }
$x_1$ & $x_2$ & $x_3$ &   & \\ \hline\hline
  0   &   0   &   0   & 0 & \\
  0   &   0   &   1   & 0 & $A_1$ \\
  0   &   1   &   0   & 0 & \\ \hline
  0   &   1   &   1   & 0 & \\
  1   &   0   &   0   & 1 & $A_2$ \\
  1   &   0   &   1   & 1 & \\ \hline
  1   &   1   &   0   & 0 & \\
  1   &   1   &   1   & 0 & $A_3$ \\
\end{tabular}
\item
die Funktion $f_{2,\mathbf{v}}^{(c)}$ f\"ur $\mathbf{v} = (1\,0\,1)^t$
und f\"ur $\mathbf{v} = (0\,1\,1)^t$

\begin{tabular}{c || c c c c c c c c  }
 $x_4$ & 0 & 1 & 0 & 1 & 0 & 1 & 0 & 1 \\
 $x_5$ & 0 & 0 & 1 & 1 & 0 & 0 & 1 & 1 \\
 $x_6$ & 0 & 0 & 0 & 0 & 1 & 1 & 1 & 1 \\ \hline
       & 1 & 0 & 0 & 1 & 0 & 0 & 0 & 0
\end{tabular}
\hskip5mm
\begin{tabular}{c || c c c c c c c c  }
 $x_4$ & 0 & 1 & 0 & 1 & 0 & 1 & 0 & 1 \\
 $x_5$ & 0 & 0 & 1 & 1 & 0 & 0 & 1 & 1 \\
 $x_6$ & 0 & 0 & 0 & 0 & 1 & 1 & 1 & 1 \\ \hline
       & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0
\end{tabular}
\end{itemize}

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